8p^2+68p-36=0

Solution for 8p^2+68p-36=0 equation:

8p^2+68p-36=0

a = 8; b = 68; c = -36;
Δ = b2-4ac
Δ = 682-4·8·(-36)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-76}{2*8}=\frac{-144}{16}
=-9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+76}{2*8}=\frac{8}{16}
=1/2
$